题解 | 顺时针旋转矩阵
顺时针旋转矩阵
https://www.nowcoder.com/practice/2e95333fbdd4451395066957e24909cc
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param mat int整型二维数组 # @param n int整型 # @return int整型二维数组 # class Solution: def rotateMatrix(self , mat: List[List[int]], n: int) -> List[List[int]]: # write code here n=len(mat) m=len(mat[0]) print(n,m) res=[] for j in range(m): temp=[] for i in range(n): temp.append(mat[i][j]) print(mat[i][j]) temp=list(reversed(temp)) #print(temp) res.append(temp) return res#刷题#