题解 | 矩阵转置
矩阵转置
https://www.nowcoder.com/practice/351b3d03e410496ab5a407b7ca3fd841
#include <stdio.h> int main() { int n = 0; int m = 0; scanf("%d %d", &n, &m); int i = 0; int j = 0; int arr[n][m]; for (i = 0; i < n; i++) { for (j = 0; j < m; j++) { scanf("%d", &arr[i][j]); } } for(i = 0; i < m; i++){ for(j = 0; j < n; j++){ printf("%d ", arr[j][i]); } printf("\n"); } return 0; }