题解 | 删除有序链表中重复的元素-I

/*
 * function ListNode(x){
 *   this.val = x;
 *   this.next = null;
 * }
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 * {1,1,2} => {1,2}
 * {} => {}
 *
 * @param head ListNode类
 * @return ListNode类
 */
function deleteDuplicates(head) {
    // write code here
    let arr = []; // 利用一个数组存储出现的元素
    let resHead = new ListNode();
    let res = resHead;
    while (head) {
        if (!arr.includes(head.val)) {
            arr.push(head.val);
            res.next = head;
            res = res.next;
        } else {
            res.next = null; // 需要处理 {1,1} 的情况，断开原有的链表
        }
        head = head.next;
    }
    return resHead.next;
}
module.exports = {
    deleteDuplicates: deleteDuplicates,
};