题解 | 输入序列不连续的序列检测
输入序列不连续的序列检测
https://www.nowcoder.com/practice/f96d0e94ec604592b502b0f1800ed8aa
`timescale 1ns/1ns
module sequence_detect(
input clk,
input rst_n,
input data,
input data_valid,
output reg match
);
reg [3:0] data_reg;
always@(posedge clk or negedge rst_n)begin
if(!rst_n)begin
data_reg <= 'b0;
end
else if(data_valid)begin
data_reg <= {data_reg[2:0],data};
end
else begin
data_reg <= data_reg;
end
end
always@(posedge clk or negedge rst_n)begin
if(!rst_n)begin
match <= 1'b0;
end
else if((data_reg[2:0] == 3'b011)&&(data==1'b0)&&(data_valid==1'b1))begin
//这里注意时序,因为data_reg相对data_valid慢一拍,所以判断条件要同时满足data_valid == 1b'1 和data_reg[2:0] == 3'b011,同时data==1'b0,但还没更新到data_reg,所以条件不能是data_reg[3:0]==4'b0110
match <= 1'b1;
end
else begin
match <= 1'b0;
end
end
endmodule