题解 | 获得积分最多的人(一)
获得积分最多的人(一)
https://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
select name, sum(grade_num) over ( partition by user_id order by user_id ) as grade_num from grade_info inner join user on grade_info.user_id = user.id order by grade_num desc limit 1