简单密码#ascii码ord() chr()
简单密码
https://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac
'''
print(ord('a'),ord('b'),ord('A'),ord('B'))
print(chr(97),chr(98),chr(65),chr(66))
print('A'.lower())
mapping={0:0,1:1,'abc':2,'def':3,'ghi':4,'jkl':5,'mno':6,'pqrs':7,'tuv':8,'wxyz':9}
print(mapping.items())
print(mapping.keys(),mapping.values())
print('s' in list(mapping.keys())[9])
'''
pw=str(input())
#mapping={0:0,1:1,2:'abc',3:'def',4:'ghi',5:'jkl',6:'mno',7:'pqrs',8:'tuv',9:'wxyz'}
#print(mapping.keys,mapping.values)
mapping=['0','1','abc','def','ghi','jkl','mno','pqrs','tuv','wxyz'] #
new_pw=''
for i in pw:
if 65<=ord(i)<=89:
new_pw += chr(ord(i.lower())+1)
elif ord(i)==90:
new_pw += 'a'
elif 97<=ord(i)<=122:
for j in mapping:
if i in j:
new_pw += str(mapping.index(j))
else:
new_pw += i
print(new_pw)
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