题解 | #牛客每个人最近的登录日期(六)#
牛客每个人最近的登录日期(六)
https://www.nowcoder.com/practice/572a027e52804c058e1f8b0c5e8a65b4
select u.name as u_n,p.date,sum(p.number) over(partition by user_id order by date)as ps_num from passing_number p left join user u on u.id=p.user_id order by date asc ,u.name asc