题解 | #字符串的排列#

import itertools
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param str string字符串 
# @return string字符串一维数组
#
class Solution:
    def Permutation(self , str: str) -> List[str]:
        n = []
        for i in str:
            n.append(i)
        ans = []
        for i in list(itertools.permutations(n)):
            ans.append(''.join(i))
        return list(set(ans))