题解 | #高精度整数加法#
高精度整数加法
https://www.nowcoder.com/practice/49e772ab08994a96980f9618892e55b6
import java.util.*;
// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
// 注意 hasNext 和 hasNextLine 的区别
while (in.hasNext()) { // 注意 while 处理多个 case
String a = in.next();
String b = in.next();
int len = Math.max(a.length(), b.length());
int alen = a.length();
int blen = b.length();
char [] arr = new char[len];
int num = 0;
for (int i = 1 ; i <= len ; i++ ) {
char ac = '0';
char bc = '0';
if (alen >= i) {
ac = a.charAt(alen - i);
}
if (blen >= i) {
bc = b.charAt(blen - i);
}
int anum = (int)( ac -'0');
int bnum = (int) (bc -'0');
int res = anum + bnum + num;
if (res >= 10 ) {
num = 1 ;
arr[len - i] = (char)(res % 10 +'0');
} else {
num = 0 ;
arr[len - i] = (char)(res +'0');
}
}
StringBuffer sbuffer = new StringBuffer();
String re = String.valueOf(arr);
if (num==1){
sbuffer.append("1");
}
sbuffer.append(re);
System.out.println(sbuffer);
}
}
}
查看9道真题和解析