题解 | #没有重复项数字的全排列#
没有重复项数字的全排列
https://www.nowcoder.com/practice/4bcf3081067a4d028f95acee3ddcd2b1
import java.util.*; public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param num int整型一维数组 * @return int整型ArrayList<ArrayList<>> */ public ArrayList<ArrayList<Integer>> permute (int[] num) { ArrayList<ArrayList<Integer>> list = new ArrayList<ArrayList<Integer>>(); ArrayList<Integer> integers = new ArrayList<>(); boolean[] used = new boolean[num.length]; int[] array = Arrays.stream(num).sorted().toArray(); generateNumbers(array,integers,list,used); return list; } private static void generateNumbers(int[] num, ArrayList<Integer> integers, ArrayList<ArrayList<Integer>> list, boolean[] used) { if(integers.size()>=num.length){ list.add(new ArrayList<>(integers)); return; } for (int i = 0; i < num.length; i++) { if(used[i]||integers.size()>=num.length){ continue; } used[i]=true; integers.add(num[i]); generateNumbers(num,integers,list,used); integers.remove(integers.size()-1); used[i]=false; } } }