题解 | #牛牛的10类人#

#include <stdio.h>
void get(int* p)
{
	int l = 0, o = 0;
	int temp = *p;
	if (temp == 0)
		o++;
	while (temp)
	{
		if (temp % 2 == 1)
			l++;
		else
			o++;
		temp /= 2;//二进制数的位数移动
	}
	if (l % 2 == 0 && o % 2 != 0)
		printf("1 ");
	else if (l % 2 != 0 && o % 2 == 0)
		printf("0 ");
	else if (l % 2 == 0 && o % 2 == 0)
		printf("10 ");
	else
		printf("100 ");
}
int main()
{
	int n = 0;
	int arr[2000] = { 0 };
	scanf("%d", &n);
	for (int i = 0; i < n; i++)
	{
		scanf("%d", &arr[i]);
		get(&arr[i]);
	}
	printf("\n");
	return 0;
}