题解 | #从单向链表中删除指定值的节点#

package main

import (
    "fmt"
)

func main() {
    n := 0
    head := 0
    fmt.Scan(&n)
    fmt.Scan(&head)

    ans := []int{head}

    for i := 0; i < n-1; i++ {
        x, y := 0, 0
        fmt.Scan(&x, &y)

        for j := 0; j < len(ans); j++ {
            if ans[j] == y {
                ans = append(append(append([]int{}, ans[:j+1]...), x), ans[j+1:]...)
                break
            }
        }
    }

    del := 0
    fmt.Scan(&del)
    for i := 0; i < len(ans); i++ {
        if ans[i] == del {
            continue
        }
        fmt.Print(ans[i], " ")
    }
 
}