题解 | #合并表记录#
合并表记录
https://www.nowcoder.com/practice/de044e89123f4a7482bd2b214a685201
n = int(input())
dict1 = {}
for i in range(n):
key, value = map(int, input().split())
if key not in dict1:
dict1[key] = value # 如果键不存在于字典中，添加新的键值对
else:
dict1[key] += value # 如果键已存在，累加它的值
# 输出所有键值对，键值对按键的顺序排序
for key in sorted(dict1.keys()):
print(f"{key} {dict1[key]}")