题解 | #重建二叉树#
重建二叉树
https://www.nowcoder.com/practice/8a19cbe657394eeaac2f6ea9b0f6fcf6
/**
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* };
*/
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param preOrder int整型一维数组
* @param preOrderLen int preOrder数组长度
* @param vinOrder int整型一维数组
* @param vinOrderLen int vinOrder数组长度
* @return TreeNode类
*/
#include <stdio.h>
int searchArr(int *Arr, int ArrLen, int p) {
int i;
for(i=0;i<ArrLen;i++) {
if(p==Arr[i])
return i;
}
return -1;
}
struct TreeNode* reConstructBinaryTree(int* preOrder, int preOrderLen, int* vinOrder, int vinOrderLen ) {
struct TreeNode* res;
int leftTreeLen, rightTreeLen;
if(!preOrderLen)
return NULL;
res = (struct TreeNode*)malloc(sizeof(struct TreeNode));
res->val = preOrder[0];
leftTreeLen = searchArr(vinOrder, vinOrderLen, preOrder[0]);
rightTreeLen = preOrderLen-1-leftTreeLen;
res->left = reConstructBinaryTree(preOrder+1, leftTreeLen, vinOrder, leftTreeLen);
res->right = reConstructBinaryTree(preOrder+1+leftTreeLen, rightTreeLen, vinOrder+leftTreeLen+1, rightTreeLen);
return res;
}
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