题解 | #提取不重复的整数#
提取不重复的整数
https://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1
#include <iostream>
#include <array>
using namespace std;
int main() {
int n;
cin >> n;
int result = 0;
array<bool, 10> numbers{false};
while (n > 0) {
int v = n % 10;
n /= 10;
if (!numbers[v]) {
numbers[v] = true;
result = result * 10 + v;
}
}
cout << result << endl;
}
