题解 | #序列重组矩阵#

//第二种写法
#include <stdio.h>

int main() {
    int n, m = 0;
    int arr[10][10] = {0};
    scanf("%d %d", &n, &m);
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < m; j++) {
            scanf("%d", &arr[i][j]);
            printf("%d ", arr[i][j]);
        }
        printf("\n");
    }
    return 0;
}