题解 | #简单密码#

inp0 = input().strip()
result_str = ''

for char in inp0:
    if char.islower():
        if char in 'abc':
            result_str +='2'
        elif char in 'def':
            result_str +='3'
        elif char in 'ghi':
            result_str +='4'
        elif char in 'jkl':
            result_str +='5'
        elif char in 'mno':
            result_str +='6'
        elif char in 'pqrs':
            result_str +='7'
        elif char in 'tuv':
            result_str +='8'
        else:
            result_str +='9'
    elif char.isupper():
        new = chr((ord(char.lower())-ord('a') + 1 ) % 26 + ord('a'))
        #print(new)
        result_str += new
    else:
        result_str +=char
print(result_str)

用了一个繁琐的方法但是排除了单独判断Z的情况