题解 | #从尾到头打印链表#rust
从尾到头打印链表
https://www.nowcoder.com/practice/d0267f7f55b3412ba93bd35cfa8e8035
/**
* #[derive(PartialEq, Eq, Debug, Clone)]
* pub struct ListNode {
* pub val: i32,
* pub next: Option<Box<ListNode>>
* }
*
* impl ListNode {
* #[inline]
* fn new(val: i32) -> Self {
* ListNode {
* val: val,
* next: None,
* }
* }
* }
*/
struct Solution{
}
impl Solution {
fn new() -> Self {
Solution{}
}
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
* @param head ListNode类
* @return int整型一维数组
*/
pub fn printListFromTailToHead(&self, head: Option<Box<ListNode>>) -> Vec<i32> {
// write code here
let mut result = Vec::new();
let mut current = head;
//要用while let解构赋值
while let Some(node) = current {
result.push(node.val);
current = node.next;
}
result.reverse();
result
}
}
option 相关知识点
https://course.rs/basic/match-pattern/option.html
while let相关知识点
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