题解 | #反转链表C语言#双指针
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* };
*/
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @return ListNode类
*/
struct ListNode* ReverseList(struct ListNode* head ) {
// write code here
struct ListNode* pre = head;
struct ListNode* cur = NULL;
struct ListNode* t;
if(head==NULL||head->next==NULL)return head;
while(pre) //遍历
{
t = pre->next;
pre->next = cur;
cur = pre;
pre = t;
}
return cur;
}
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