题解 | #简单计算器#
简单计算器
https://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239
#include <stdio.h>
int main() {
double n1 = 0.0;
double n2 = 0.0;
char op = 0;
while (~scanf("%lf%c%lf", &n1, &op, &n2)) {
switch (op) {
case'+':
printf("%.4lf+%.4lf=%.4lf\n", n1, n2, n1 + n2);
break;
case'-':
printf("%.4lf-%.4lf=%.4lf\n", n1, n2, n1 - n2);
break;
case'*':
printf("%.4lf*%.4lf=%.4lf\n", n1, n2, n1 * n2);
break;
case'/':
if (0.0 == n2) {
printf("Wrong!Division by zero!\n");
} else {
printf("%.4lf/%.4lf=%.4lf\n", n1, n2, n1 / n2);
}
break;
default:
printf("Invalid operation!\n");
break;
}
}
return 0;
}
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