题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
import java.util.*;
/*
* public class ListNode {
* int val;
* ListNode next = null;
* public ListNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @param m int整型
* @param n int整型
* @return ListNode类
*/
public ListNode reverseBetween (ListNode head, int m, int n) {
// write code here
if(head != null && head.next != null && m != n) {
ListNode cur = head;
int tm = m, tn = n - m;
//找到需要翻转区间的起始端点(s,e),和端点区间左右相邻点(left,right)
ListNode left = null;
while(tm-->1) {
left = cur;
cur = cur.next;
}
ListNode s = cur;
while(tn-->0) {
cur = cur.next;
}
ListNode e = cur;
ListNode right = cur.next;
//链表翻转
e.next = null;
ListNode pre = null;
cur = s;
while(cur != null) {
ListNode tmp = cur.next;
cur.next = pre;
pre = cur;
cur = tmp;
}
//补齐: left->(e,s)->right
if(left != null) {
left.next = e;
}
s.next = right;
//注意输出表头
return left == null ? e : head;
}
return head;
}
}
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