题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param nums int整型一维数组
* @param numsLen int nums数组长度
* @param target int整型
* @return int整型
*/
int search(int* nums, int numsLen, int target ) {
// write code here
int left = 0;
int right = numsLen - 1; //注意一下
int mid;
if (numsLen == 0)
return -1;
while (left <= right) {
mid = (right + left) / 2;
if (nums[mid] < target) {
left = mid + 1;
} else if (nums[mid] > target) {
right = mid - 1;
} else {
return mid;
}
}
return -1;
}
