题解 | #牛群的树形结构重建II#
牛群的树形结构重建II
https://www.nowcoder.com/practice/ad81ec30cca0477e82e33334a652a6ae
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param preOrder int整型一维数组
* @param inOrder int整型一维数组
* @return TreeNode类
*/
public TreeNode buildTreeII (int[] preOrder, int[] inOrder) {
// write code here
if(preOrder.length == 0){
return null;
}
int rootVal = preOrder[0];
TreeNode result = new TreeNode(rootVal);
int index = findRootIndex(inOrder,rootVal);
TreeNode left = buildTreeII(Arrays.copyOfRange(preOrder,1,index+1),Arrays.copyOfRange(inOrder,0,index));
TreeNode right = buildTreeII(Arrays.copyOfRange(preOrder,index+1,preOrder.length),Arrays.copyOfRange(inOrder,index+1,inOrder.length));
result.left = left;
result.right = right;
return result;
}
public int findRootIndex(int[] arr,int rootVal){
for(int i = 0;i < arr.length;i++){
if(arr[i] == rootVal){
return i;
}
}
return -1;
}
}

