题解 | #两个链表的第一个公共结点#
两个链表的第一个公共结点
https://www.nowcoder.com/practice/6ab1d9a29e88450685099d45c9e31e46
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
#
# @param pHead1 ListNode类
# @param pHead2 ListNode类
# @return ListNode类
#
# 设置两个指针,分别以同样的速度遍历两个链表。当两个指针在同一个节点相遇时,说明这个节点就是第一个公共节点
# 当两个指针经过多轮遍历,最后同时回到了两个链表头时,说明没有公共节点
class Solution:
def FindFirstCommonNode(self , pHead1 , pHead2 ):
node1, node2 = pHead1, pHead2
if node1 == None or node2 == None:
return None
count = 0
while True:
if node1 == None:
node1 = pHead1
if node2 == None:
node2 = pHead2
if node1 == node2:
return node1
elif node1 == pHead1 and node2 == pHead2 and count != 0:
return None
node1 = node1.next
node2 = node2.next
count += 1


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