题解 | #字符串操作#

#include<stdio.h>
int main()
{
    int n, m;
    char s[100];
    scanf("%d %d", &n, &m);
    scanf("%s", s);
    for (int i = 0; i < m; i++)
    {
        int l, r;
        char c1, c2;
        scanf("%d %d %c %c", &l, &r, &c1, &c2);
        for (int j = l-1; j <= r-1; j++)
        {
            if (s[j] == c1)
                s[j] = c2;
        }
    }
    printf("%s", s);
    return 0;
}