题解 | #人民币转换#

n,l=map(int,input().split('.'))
s='人民币'
dic={1:'壹',2:'贰',3:'叁',4:'肆',5:'伍',6:'陆',7:'柒',8:'捌',9:'玖'}
def fun(n,s=''):
    if n<10:
        s+=dic[n]
    elif n<100:
        if n==10:
            s+='拾'
        elif n<20:
            s+='拾'+fun(n%10)
        elif n%10==0:
            s+=dic[n//10]+'拾'
        else:
            s+=dic[n//10]+'拾'+fun(n%10)
    elif n<1000:
        if n%100==0:
            s+=dic[n//100]+'佰'
        elif n%10!=0:
            s+=dic[n//100]+'佰'+fun(n%100)
        else:
            s+=dic[n//100]+'佰零'+fun(n%100)
    elif n<10000:
        if n%1000==0:     
            s+=dic[n//1000]+'仟'
        elif n%100!=0:
            s+=dic[n//1000]+'仟'+fun(n%1000)
        else:
            s+=dic[n//1000]+'仟零'+fun(n%1000)
    elif n<100000000:
        if n%10000==0:     
            s+=fun(n//10000)+'万'
        elif n%1000!=0:
            s+=fun(n//10000)+'万'+fun(n%10000)
        else:
            s+=fun(n//10000)+'万零'+fun(n%10000)
    else:
        if n%100000000==0:
            s+=fun(n//100000000)+'亿'
        elif n%10000000!=0:
            s+=fun(n//100000000)+'亿'+fun(n%100000000)
        else:
            s+=fun(n//100000000)+'亿零'+fun(n%100000000)
    return s
if n>0:
   s+=fun(n)+'元'
if l==0:
    s+='整'
elif l<10:
    s+=dic[l]+'分'
elif l%10==0:
    s+=dic[l//10]+'角'
else:
    s+=dic[l//10]+'角'+dic[l%10]+'分'
print(s)