题解 | #二叉树的镜像#
二叉树的镜像
https://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param pRoot TreeNode类
# @return TreeNode类
#
from collections import deque
class Solution:
def Mirror(self , pRoot: TreeNode) -> TreeNode:
# write code here
if not pRoot:
return None
queue = deque()
queue.append(pRoot)
while queue:
for _ in range(len(queue)):
node = queue.popleft()
node.left, node.right = node.right, node.left
if node.left: queue.append(node.left)
if node.right: queue.append(node.right)
return pRoot
背诵层次遍历模板,直接对调node的left和right即可。

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