题解 | #牛牛学数列3#
牛牛学数列3
https://www.nowcoder.com/practice/f65c726d081c4160a9356eabf0dc21d9
#include <stdio.h>
int main() {
int input;
int j1=-1;
int j2;
int sum=0;
double all=0;
scanf("%d",&input);
for(int i=1;i<=input;i++)
{
j1=j1+2;
j2=j1;
if(i%2==0)
{
j2=-j1;
}
sum=sum+j2;
all=all+1.0/sum;
}
printf("%.3lf",all);
return 0;
}
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