题解 | #旋转数组的最小数字#

class Solution {
public:
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     * 
     * @param nums int整型vector 
     * @return int整型
     */
    int minNumberInRotateArray(vector<int>& nums) {
        // write code here
        int left = 0;
        int right = nums.size() - 1;
        while (left < right) {
            int mid = (left + right) / 2;
            if (nums[mid] > nums[right]) {
                left = mid + 1;
            } else if (nums[mid] == nums[right]) {
                right--;
            } else if (nums[mid] < nums[right]) {
                right = mid;
            }
        }

        return nums[left];
    }
};