题解 | #牛牛的循环牧场#
牛牛的循环牧场
https://www.nowcoder.com/practice/a651e248e5ad46ccb0a56a0e4e538113
class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型vector * @return bool布尔型 */ int nextstep(vector<int>& nums, int curr_step){ int temp = (curr_step + nums[curr_step]); if ( temp < 0) { curr_step = temp + nums.size(); } else if( temp >= nums.size()){ curr_step = (temp - nums.size()); } else { curr_step = temp; } return curr_step; } bool get_sign(int num){ if (num < 0) return false; else return true; } bool set_state(int index, vector<int>& nums, vector<bool>& state, bool sign){ state[index] = true; int next = nextstep(nums, index); if ((sign ^ get_sign(nums[next]))) return false; if (next == index) return false; if (state[next] == true) return true; return set_state(next, nums, state, sign); } bool checkCircularArray(vector<int>& nums) { // write code here for(int i = 0; i < nums.size(); ++i){ vector<bool> state(nums.size(), false); bool sign = get_sign(nums[i]); if (set_state(i, nums, state, sign)) return true; } return false; } };