线性查找脑残法
查找
https://www.nowcoder.com/practice/d93db01c2ee44e8a9237d63842aca8aa
#include <iostream>
using namespace std;
int main() {
int n, m, f = 0;
cin >> n;
int* a = (int*)malloc(sizeof(int) * n);
for (int i = 0; i < n; ++i) {
cin >> a[i];
}
cin >> m;
int* b = (int*)malloc(sizeof(int) * m);
for (int i = 0; i < m; ++i) {
cin >> b[i];
}
for (int i = 0; i < m; ++i) {
f = 0;
for (int j = 0; j < n; ++j) {
if (a[j] == b[i]) {
f = 1;
std::cout << "YES" << std::endl;
break;//主动退出循环
}
}
if (f == 0) {
std::cout << "NO" << std::endl;
}
}
}


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