题解 | #高精度整数加法#

#include <stdio.h>
#include <string.h>

int main() {
    char str1[100],str2[100];
    scanf("%s",str1);
    scanf("%s",str2);
    int len1 = strlen(str1);
    int len2 = strlen(str2);
    char* max_str;
    char* min_str;
    int len_max = len1>=len2?len1:len2;
    if(len_max==len1)
    {
        max_str = str1;
        min_str = str2;
    }
    else {
        max_str = str2;
        min_str = str1;
    }
    int plus =0;
    int a,b;
    int sum =0;
    int reverse[1000] = {0};
    int count=0;
    for(int j=0;j<strlen(min_str);j++)
    {
        a = max_str[len_max-1-j]-'0';
        b = min_str[strlen(min_str)-1-j]-'0';
        sum = a+b+plus;
        plus =sum/10;
        sum = sum%10;
        reverse[count++] = sum;
    }
    for(int j=strlen(max_str)-strlen(min_str)-1;j>=0;j--)
    {
        sum = max_str[j]-'0'+plus;
        plus =sum/10;
        sum = sum%10;
        reverse[count++] = sum;
    }
    if(plus>0)
    {
        reverse[count++] = plus;
    }
    for(int i=count-1;i>=0;i--)
    {
        printf("%d",reverse[i]);
    }
    return 0;
}