题解 | #N个数之和#
N个数之和
https://www.nowcoder.com/practice/b007744eb43b4f7b95d9e87de01528db
#include <iostream> #include <malloc.h> using namespace std; int main(void) { int N, sum = 0; cin>>N; int * p = (int *)malloc(sizeof(int) * N); for(int i = 0;i < N;++i) { cin >> p[i]; sum += p[i]; } cout << sum; return 0; }