环形链表的约瑟夫问题
https://www.nowcoder.com/practice/41c399fdb6004b31a6cbb047c641ed8a
class Solution {
public:
/**
*
* @param n int整型
* @param m int整型
* @return int整型
*/
int ysf(int n, int m) {
// write code here
int i = 1;
int idx = 0;
while(i <= n){
idx = (idx + m) % i;
++i;
}
return idx + 1;
}
};
思路：数学计算
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球球与墩墩：这不是前端常考的对象扁平化吗，面试官像是前端出来的
const flattern = (obj) => {
const res = {};
const dfs = (curr, path) => {
if(typeof curr === 'object' && curr !== null) {
const isArray = Array.isArray(curr);
for(let key in curr) {
const newPath = path ? isArray ? `${path}[${key}]` : `${path}.${key}` : key;
dfs(curr[key], newPath);
}
} else {
res[path] = curr
}
}
dfs(obj);
return res;
}
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