题解 | #滑动窗口的最大值#

import java.util.*;
public class Solution {
    public ArrayList<Integer> maxInWindows(int [] num, int size) {
        ArrayList<Integer> list = new ArrayList<>();
        //如果数组长度为0或窗口大小为0则为null
        if (num.length < size||size==0) {
            return list;
        }
        //根据循环一层一层找窗口的最大值然后添加进到list中
        for (int i = 0; i <= num.length - size; i++) {
            int max=num[i];
            for (int j = i; j < i+size; j++) {
                if(num[j]>max){
                    max=num[j];
                }
            }
            list.add(max);
        }

        return list;
    }
}