题解 | #删除有序链表中重复的元素-I#

/**
 * struct ListNode {
 *  int val;
 *  struct ListNode *next;
 * };
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 *
 * @param head ListNode类
 * @return ListNode类
 */
struct ListNode* deleteDuplicates(struct ListNode* head ) {
    // write code here
    struct ListNode* dest = head;

    while (dest) {
        if (!dest->next) {
            return head;
        }
        struct ListNode* cur = dest->next;
        while (cur) {
            if (cur->val == dest->val) {
                dest->next = cur->next;
            }
            cur = cur->next;
        }
        dest = dest->next;
    }
    return head;
}