题解 | #在字符串中找出连续最长的数字串#

import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNextLine()) {
            String s = in.nextLine();
            int maxDigitLen = 0;
            int curLen = 0;
            for (int i = 0 ; i < s.length() ; ++i) {
                char c = s.charAt(i);
                if (Character.isDigit(c)) {
                    ++curLen;
                } else {
                    maxDigitLen = Math.max(curLen, maxDigitLen);
                    curLen = 0;
                }
            }
            maxDigitLen = Math.max(maxDigitLen, curLen);//结尾部分
            StringBuilder sb = new StringBuilder();
            int begin = 0;
            boolean flag = false;
            curLen = 0;
            for (int i = 0 ; i < s.length() ; ++i) {
                char c = s.charAt(i);
                if (Character.isDigit(c)) {
                    if (!flag) {
                        begin = i;
                        flag = true;
                    }
                    curLen++;
                } else {
                    flag = false;
                    if (curLen == maxDigitLen) {
                        sb.append(s.substring(begin, begin + maxDigitLen));
                    }
                    curLen = 0;
                }
            }
            if (curLen == maxDigitLen) { //结尾部分
                sb.append(s.substring(begin, begin + maxDigitLen));
            }
            System.out.println(sb.toString() + "," + maxDigitLen);
        }
    }
}