题解 | #两个链表的第一个公共结点#

/*
public class ListNode {
    int val;
    ListNode next = null;

    ListNode(int val) {
        this.val = val;
    }
}*/
public class Solution {
    public ListNode FindFirstCommonNode(ListNode pHead1, ListNode pHead2) {
        if ( pHead1 == null || pHead2 == null) {
            return null;
        }
        ListNode p1 = pHead1;
        ListNode p2 = pHead2;

        while ( p1 != p2) {
            p1 = (p1 == null) ? pHead2 : p1.next;
            p2 = (p2 == null) ? pHead1 : p2.next;
        }

        return p1;

    }
}