题解 | #旋转数组的最小数字#
旋转数组的最小数字
https://www.nowcoder.com/practice/9f3231a991af4f55b95579b44b7a01ba
class Solution {
public:
int minNumberInRotateArray(vector<int> rotateArray) {
int l = 0;
int r = rotateArray.size() - 1;
while (l <= r) {
int mid = l + (r - l) / 2;
if (rotateArray[mid] > rotateArray[r]) {
l = mid + 1;
} else if (rotateArray[mid] < rotateArray[r]) {
r = mid;
} else {
r--;
}
}
return rotateArray[l];
}
};
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