题解 | #统计字符串中子串出现的次数#
统计字符串中子串出现的次数
https://www.nowcoder.com/practice/9eb684f845a446f3b121472de2ea75cd
#include <iostream>
#include <cstring>
using namespace std;
int strtimes(char *str,char *substr){
int count=0;
int len1=strlen(str);
int len2=strlen(substr);
for(int i=0;i<len1;i++){
for(int j=0;j<len2;j++){
if((substr[j]==str[j+i])&&(j==len2-1)) {
count+=1;
break;
}
else if(str[j+i]==substr[j]){
continue;
}
else break;
}
}
return count;
}
int main() {
char str[100] = { 0 };
char substr[100] = { 0 };
cin.getline(str, sizeof(str));
cin.getline(substr, sizeof(substr));
int count = 0;
// write your code here......
count=strtimes(str,substr);
cout << count << endl;
return 0;
}
