题解 | #取近似值#

#include <iostream>
#include<sstream>
using namespace std;

int main() {

    string x;
    cin>>x;
    stringstream geek(x);
    double y;
    geek>>y;
    int ans=(int)y;
    int a;
    for(int i=0;i<x.length();i++){
        if(x[i]=='.'){
            a=x[i+1]-'0';
            break;
        }
    }
    if(a>=5){
        ans++;
    }
    cout<<ans;


    return 0;
}
// 64 位输出请用 printf("%lld")