题解 | #鸡兔同笼#
鸡兔同笼
https://www.nowcoder.com/practice/fda725b4d9a14010bb145272cababef1
#include<cstdio>
int main(){
int n;
while (scanf("%d", &n) != EOF){
if (n % 2 == 1){
printf("0 0\n");
}
else{
int min,max;
max = n / 2;
if (n % 4 != 0){
min = n / 4 + 1;
}
else{
min = n / 4;
}
printf("%d %d\n", min, max);
}
}
}
联想公司福利 1523人发布
