题解 | #二叉树根节点到叶子节点和为指定值的路径#
二叉树根节点到叶子节点和为指定值的路径
https://www.nowcoder.com/practice/840dd2dc4fbd4b2199cd48f2dadf930a
记录:
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* }
*/
public class Solution {
/**
*
* @param root TreeNode类
* @param sum int整型
* @return int整型ArrayList<ArrayList<>>
*/
public ArrayList<ArrayList<Integer>> pathSum (TreeNode root, int sum) {
// write code here
ArrayList<ArrayList<Integer>> out = new ArrayList<>();
if (root == null) {
return out;
} else {
Stack<TreeNode> st = new Stack<>();
Stack<ArrayList<Integer>> stp = new Stack<>();
ArrayList<Integer> path = new ArrayList<>();
path.add(root.val);
st.add(root);
stp.add(path);
while (!st.isEmpty()) {
TreeNode temp = st.pop();
ArrayList<Integer> tempp = stp.pop();
if (temp.left == null && temp.right == null) {
int sumtemp = tempp.stream().mapToInt(n -> n).sum();
if (sumtemp == sum) {
out.add(tempp);
}
}
if (temp.right != null) {
st.push(temp.right);
tempp.add(temp.right.val);
stp.push(new ArrayList<>(tempp));
tempp.remove(tempp.size() - 1);
}
if (temp.left != null) {
st.push(temp.left);
tempp.add(temp.left.val);
stp.push(new ArrayList<>(tempp));
tempp.remove(tempp.size() - 1);
}
}
return out;
}
}
}


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