题解 | #守形数#

#include <iostream>

using namespace std;

int main() {
    int n;
    while(cin >> n){
        int sq = n * n;
        int flag = 0;
        while(sq && n){
            int a = sq % 10;
            int b = n % 10;
            if(a != b){
                flag = 1;
                break;
            }
            sq /= 10;
            n /= 10;
        }
        if(flag) cout << "No!" << endl;
        else cout << "Yes!" << endl;
    }
    return 0;
}