题解 | #数字颠倒#
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <stdio.h>
int main() {
int a = 0,i = 0;
scanf("%d",&a);
if(a == 0)
{
printf("%d",a);
}
int arr[32] = {0};
while(a!=0)
{
arr[i++] = a%10;
a /= 10;
}
for(int j = 0;j<i;j++)
{
printf("%d",arr[j]);
}
return 0;
}
