题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> #include<math.h> int main() { long long a = 2; scanf("%lld",&a); printf("%lld",(long long)pow(2,a)); }
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> #include<math.h> int main() { long long a = 2; scanf("%lld",&a); printf("%lld",(long long)pow(2,a)); }
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