题解 | #兔子的数量#
兔子的数量
https://www.nowcoder.com/practice/8783056676de4396b0bf816a3561d62f
num = int(input())
def fac(n):
res = [2, 3]
if n == 1:
return 2
if n == 2:
return 3
for i in range(3, n + 1):
res.append(res[i - 2] + res[i - 3])
return res[n - 1]
print(fac(num))
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