题解 | #数字颠倒#
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <iostream>
using namespace std;
int main() {
int num;
char tmp;
cin >> num;
if (num == 0)
cout << '0';
while(num){
tmp = num%10 + '0';
cout << tmp;
num/=10;
}
return 0;
}
// 64 位输出请用 printf("%lld")
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