题解 | #字符串归一化#
字符串归一化
https://www.nowcoder.com/practice/6d5e036defdf408681376a4a9d4930ff
ss = input()
dd = {}
for i in ss:
if i in dd:
dd[i] += 1
else:
dd[i] = 1
dd = sorted(dd.items(),key = lambda x:x[0])
dd = {i[0]:i[1] for i in dd}
ans = ''
for item in dd.items():
ans += item[0]
ans += str(item[1])
print(ans)
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