题解 | #判断是不是二叉搜索树#
判断是不是二叉搜索树
https://www.nowcoder.com/practice/a69242b39baf45dea217815c7dedb52b
中序遍历,从小到大
import java.util.*; /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param root TreeNode类 * @return bool布尔型 */ public boolean isValidBST (TreeNode root) { // write code here // 中序遍历, 从小到大 if (root == null) return true; LinkedList<TreeNode> st = new LinkedList<>(); TreeNode temp = root; int pre = -Integer.MIN_VALUE; while (!st.isEmpty() || temp != null) { while (temp != null) { st.push(temp); temp = temp.left; } TreeNode t = st.poll(); int now = t.val; if (pre > now) return false; pre = now; temp = t.right; } return true; } }